3j^2+19j+16=0

Solution for 3j^2+19j+16=0 equation:

Simplifying
3j2 + 19j + 16 = 0

Reorder the terms:
16 + 19j + 3j2 = 0

Solving
16 + 19j + 3j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(16 + 3j)(1 + j) = 0

Subproblem 1
Set the factor '(16 + 3j)' equal to zero and attempt to solve:

Simplifying
16 + 3j = 0

Solving
16 + 3j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 3j = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 3j = 0 + -16
3j = 0 + -16

Combine like terms: 0 + -16 = -16
3j = -16

Divide each side by '3'.
j = -5.333333333

Simplifying
j = -5.333333333
Subproblem 2
Set the factor '(1 + j)' equal to zero and attempt to solve:

Simplifying
1 + j = 0

Solving
1 + j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + j = 0 + -1
j = 0 + -1

Combine like terms: 0 + -1 = -1
j = -1

Simplifying
j = -1
Solution
j = {-5.333333333, -1}